Base | Representation |
---|---|
bin | 1011110110100001000111… |
… | …0110010000010001001011 |
3 | 1201010202212211122122002102 |
4 | 2331220101312100101023 |
5 | 3202000424413224042 |
6 | 43414244200224015 |
7 | 2513322014123561 |
oct | 275502166202113 |
9 | 51122784578072 |
10 | 13031230211147 |
11 | 4174571804655 |
12 | 156565876b00b |
13 | 736abbb91ab5 |
14 | 330a019c5a31 |
15 | 178e8b2b7b32 |
hex | bda11d9044b |
13031230211147 has 2 divisors, whose sum is σ = 13031230211148. Its totient is φ = 13031230211146.
The previous prime is 13031230211143. The next prime is 13031230211177. The reversal of 13031230211147 is 74111203213031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13031230211147 - 22 = 13031230211143 is a prime.
It is not a weakly prime, because it can be changed into another prime (13031230211143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515615105573 + 6515615105574.
It is an arithmetic number, because the mean of its divisors is an integer number (6515615105574).
Almost surely, 213031230211147 is an apocalyptic number.
13031230211147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13031230211147 is an equidigital number, since it uses as much as digits as its factorization.
13031230211147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 13031230211147 its reverse (74111203213031), we get a palindrome (87142433424178).
The spelling of 13031230211147 in words is "thirteen trillion, thirty-one billion, two hundred thirty million, two hundred eleven thousand, one hundred forty-seven".
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