Search a number
-
+
13031312353 = 108791119783
BaseRepresentation
bin11000010001011101…
…00000101111100001
31020122011201020221021
430020232200233201
5203142003443403
65553030125441
7640633220203
oct141056405741
936564636837
1013031312353
115587921934
1226381b0881
1312c8a16117
148b899a773
155140898bd
hex308ba0be1

13031312353 has 4 divisors (see below), whose sum is σ = 13031540928. Its totient is φ = 13031083780.

The previous prime is 13031312351. The next prime is 13031312387. The reversal of 13031312353 is 35321313031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13031312353 - 21 = 13031312351 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13031312351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48900 + ... + 168682.

It is an arithmetic number, because the mean of its divisors is an integer number (3257885232).

Almost surely, 213031312353 is an apocalyptic number.

It is an amenable number.

13031312353 is a deficient number, since it is larger than the sum of its proper divisors (228575).

13031312353 is a wasteful number, since it uses less digits than its factorization.

13031312353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 228574.

The product of its (nonzero) digits is 2430, while the sum is 25.

Adding to 13031312353 its reverse (35321313031), we get a palindrome (48352625384).

The spelling of 13031312353 in words is "thirteen billion, thirty-one million, three hundred twelve thousand, three hundred fifty-three".

Divisors: 1 108791 119783 13031312353