Base | Representation |
---|---|
bin | 111100101011101001… |
… | …0001101101110011011 |
3 | 110110100202200012100112 |
4 | 1321113102031232123 |
5 | 4113340213131413 |
6 | 135510512354535 |
7 | 12262200502313 |
oct | 1712722155633 |
9 | 413322605315 |
10 | 130313411483 |
11 | 502a1583892 |
12 | 21309845a4b |
13 | c399ab9c08 |
14 | 6442d70443 |
15 | 35ca6212a8 |
hex | 1e5748db9b |
130313411483 has 2 divisors, whose sum is σ = 130313411484. Its totient is φ = 130313411482.
The previous prime is 130313411411. The next prime is 130313411491. The reversal of 130313411483 is 384114313031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130313411483 - 214 = 130313395099 is a prime.
It is not a weakly prime, because it can be changed into another prime (130313411183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65156705741 + 65156705742.
It is an arithmetic number, because the mean of its divisors is an integer number (65156705742).
Almost surely, 2130313411483 is an apocalyptic number.
130313411483 is a deficient number, since it is larger than the sum of its proper divisors (1).
130313411483 is an equidigital number, since it uses as much as digits as its factorization.
130313411483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 32.
The spelling of 130313411483 in words is "one hundred thirty billion, three hundred thirteen million, four hundred eleven thousand, four hundred eighty-three".
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