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130320022057 is a prime number
BaseRepresentation
bin111100101011110101…
…1011011101000101001
3110110101020010001100121
41321113223123220221
54113343411201212
6135511310203241
712262310624161
oct1712753335051
9413336101317
10130320022057
11502a5289475
122130bab3521
13c39b292ab4
146443bb15a1
1535caec9d07
hex1e57adba29

130320022057 has 2 divisors, whose sum is σ = 130320022058. Its totient is φ = 130320022056.

The previous prime is 130320021991. The next prime is 130320022087. The reversal of 130320022057 is 750220023031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127955728681 + 2364293376 = 357709^2 + 48624^2 .

It is an emirp because it is prime and its reverse (750220023031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130320022057 is a prime.

It is a super-2 number, since 2×1303200220572 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130320022087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65160011028 + 65160011029.

It is an arithmetic number, because the mean of its divisors is an integer number (65160011029).

Almost surely, 2130320022057 is an apocalyptic number.

It is an amenable number.

130320022057 is a deficient number, since it is larger than the sum of its proper divisors (1).

130320022057 is an equidigital number, since it uses as much as digits as its factorization.

130320022057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 25.

Adding to 130320022057 its reverse (750220023031), we get a palindrome (880540045088).

The spelling of 130320022057 in words is "one hundred thirty billion, three hundred twenty million, twenty-two thousand, fifty-seven".