13032111312331 has 4 divisors (see below), whose sum is σ = 13032134388432. Its totient is φ = 13032088236232.

The previous prime is 13032111312323. The next prime is 13032111312349. The reversal of 13032111312331 is 13321311123031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13032111312331 - 2³ = 13032111312323 is a prime.

It is a super-2 number, since 2×13032111312331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13032111312296 and 13032111312305.

It is not an unprimeable number, because it can be changed into a prime (13032111312361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10669120 + ... + 11827693.

It is an arithmetic number, because the mean of its divisors is an integer number (3258033597108).

Almost surely, 2^{13032111312331} is an apocalyptic number.

13032111312331 is a deficient number, since it is larger than the sum of its proper divisors (23076101).

13032111312331 is an equidigital number, since it uses as much as digits as its factorization.

13032111312331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23076100.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13032111312331 its reverse (13321311123031), we get a palindrome (26353422435362).

The spelling of 13032111312331 in words is "thirteen trillion, thirty-two billion, one hundred eleven million, three hundred twelve thousand, three hundred thirty-one".