Base | Representation |
---|---|
bin | 10010111101101101100… |
… | …100010011001111000001 |
3 | 11121120211011210011222120 |
4 | 102331231210103033001 |
5 | 132322440102320301 |
6 | 2434404332154453 |
7 | 163103561321526 |
oct | 22755544231701 |
9 | 4546734704876 |
10 | 1303213323201 |
11 | 462764a454a9 |
12 | 1906a3608a29 |
13 | 95b7aa4c30a |
14 | 4710c24114d |
15 | 23d760a5e36 |
hex | 12f6d9133c1 |
1303213323201 has 4 divisors (see below), whose sum is σ = 1737617764272. Its totient is φ = 868808882132.
The previous prime is 1303213323193. The next prime is 1303213323211. The reversal of 1303213323201 is 1023233123031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1303213323201 - 23 = 1303213323193 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1303213323211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217202220531 + ... + 217202220536.
It is an arithmetic number, because the mean of its divisors is an integer number (434404441068).
Almost surely, 21303213323201 is an apocalyptic number.
It is an amenable number.
1303213323201 is a deficient number, since it is larger than the sum of its proper divisors (434404441071).
1303213323201 is an equidigital number, since it uses as much as digits as its factorization.
1303213323201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 434404441070.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 1303213323201 its reverse (1023233123031), we get a palindrome (2326446446232).
The spelling of 1303213323201 in words is "one trillion, three hundred three billion, two hundred thirteen million, three hundred twenty-three thousand, two hundred one".
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