13032133323113 has 4 divisors (see below), whose sum is σ = 13166485213140. Its totient is φ = 12897781433088.

The previous prime is 13032133323067. The next prime is 13032133323119. The reversal of 13032133323113 is 31132333123031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4122576950569 + 8909556372544 = 2030413^2 + 2984888^2 .

It is a cyclic number.

It is not a de Polignac number, because 13032133323113 - 2¹² = 13032133319017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13032133323119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67175944868 + ... + 67175945061.

It is an arithmetic number, because the mean of its divisors is an integer number (3291621303285).

Almost surely, 2^{13032133323113} is an apocalyptic number.

It is an amenable number.

13032133323113 is a deficient number, since it is larger than the sum of its proper divisors (134351890027).

13032133323113 is an equidigital number, since it uses as much as digits as its factorization.

13032133323113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134351890026.

The product of its (nonzero) digits is 8748, while the sum is 29.

Adding to 13032133323113 its reverse (31132333123031), we get a palindrome (44164466446144).

The spelling of 13032133323113 in words is "thirteen trillion, thirty-two billion, one hundred thirty-three million, three hundred twenty-three thousand, one hundred thirteen".