Base | Representation |
---|---|
bin | 1011110110100101001001… |
… | …0101110000111000001011 |
3 | 1201010212200020122000121020 |
4 | 2331221102111300320023 |
5 | 3202010133411304003 |
6 | 43414543411243523 |
7 | 2513360563026126 |
oct | 275512225607013 |
9 | 51125606560536 |
10 | 13032312213003 |
11 | 4174a77546666 |
12 | 15658baba95a3 |
13 | 736c320b0595 |
14 | 330aa559b3bd |
15 | 179001295d53 |
hex | bda52570e0b |
13032312213003 has 8 divisors (see below), whose sum is σ = 17535832947600. Its totient is φ = 8608499810208.
The previous prime is 13032312213001. The next prime is 13032312213007. The reversal of 13032312213003 is 30031221323031.
13032312213003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13032312213003 - 21 = 13032312213001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13032312213001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19927082568 + ... + 19927083221.
It is an arithmetic number, because the mean of its divisors is an integer number (2191979118450).
Almost surely, 213032312213003 is an apocalyptic number.
13032312213003 is a deficient number, since it is larger than the sum of its proper divisors (4503520734597).
13032312213003 is a wasteful number, since it uses less digits than its factorization.
13032312213003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39854165901.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 13032312213003 its reverse (30031221323031), we get a palindrome (43063533536034).
The spelling of 13032312213003 in words is "thirteen trillion, thirty-two billion, three hundred twelve million, two hundred thirteen thousand, three".
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