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13032312213003 = 310939854165789
BaseRepresentation
bin1011110110100101001001…
…0101110000111000001011
31201010212200020122000121020
42331221102111300320023
53202010133411304003
643414543411243523
72513360563026126
oct275512225607013
951125606560536
1013032312213003
114174a77546666
1215658baba95a3
13736c320b0595
14330aa559b3bd
15179001295d53
hexbda52570e0b

13032312213003 has 8 divisors (see below), whose sum is σ = 17535832947600. Its totient is φ = 8608499810208.

The previous prime is 13032312213001. The next prime is 13032312213007. The reversal of 13032312213003 is 30031221323031.

13032312213003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13032312213003 - 21 = 13032312213001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13032312213001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19927082568 + ... + 19927083221.

It is an arithmetic number, because the mean of its divisors is an integer number (2191979118450).

Almost surely, 213032312213003 is an apocalyptic number.

13032312213003 is a deficient number, since it is larger than the sum of its proper divisors (4503520734597).

13032312213003 is a wasteful number, since it uses less digits than its factorization.

13032312213003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39854165901.

The product of its (nonzero) digits is 1944, while the sum is 24.

Adding to 13032312213003 its reverse (30031221323031), we get a palindrome (43063533536034).

The spelling of 13032312213003 in words is "thirteen trillion, thirty-two billion, three hundred twelve million, two hundred thirteen thousand, three".

Divisors: 1 3 109 327 39854165789 119562497367 4344104071001 13032312213003