Base | Representation |
---|---|
bin | 1011110110100101001011… |
… | …0100010010000000100111 |
3 | 1201010212200210200110120120 |
4 | 2331221102310102000213 |
5 | 3202010142433304111 |
6 | 43414544254533023 |
7 | 2513361021025620 |
oct | 275512264220047 |
9 | 51125623613516 |
10 | 13032320213031 |
11 | 4174a81010159 |
12 | 1565901807173 |
13 | 736c33951a22 |
14 | 330aa6680a47 |
15 | 179001d26406 |
hex | bda52d12027 |
13032320213031 has 16 divisors (see below), whose sum is σ = 19862835744000. Its totient is φ = 7445516839488.
The previous prime is 13032320213009. The next prime is 13032320213047. The reversal of 13032320213031 is 13031202323031.
It is not a de Polignac number, because 13032320213031 - 215 = 13032320180263 is a prime.
It is a super-2 number, since 2×130323202130312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13032320212992 and 13032320213010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13032320213071) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63364981 + ... + 63570318.
It is an arithmetic number, because the mean of its divisors is an integer number (1241427234000).
Almost surely, 213032320213031 is an apocalyptic number.
13032320213031 is a deficient number, since it is larger than the sum of its proper divisors (6830515530969).
13032320213031 is a wasteful number, since it uses less digits than its factorization.
13032320213031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126940198.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 13032320213031 its reverse (13031202323031), we get a palindrome (26063522536062).
The spelling of 13032320213031 in words is "thirteen trillion, thirty-two billion, three hundred twenty million, two hundred thirteen thousand, thirty-one".
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