Base | Representation |
---|---|
bin | 111100101011111100… |
… | …0011110111011110001 |
3 | 110110101110112212121112 |
4 | 1321113320132323301 |
5 | 4113400300142231 |
6 | 135511511403105 |
7 | 12262351664102 |
oct | 1712770367361 |
9 | 413343485545 |
10 | 130323443441 |
11 | 502a7205a64 |
12 | 21311083495 |
13 | c39bbc0199 |
14 | 64444223a9 |
15 | 35cb45392b |
hex | 1e57e1eef1 |
130323443441 has 2 divisors, whose sum is σ = 130323443442. Its totient is φ = 130323443440.
The previous prime is 130323443429. The next prime is 130323443491. The reversal of 130323443441 is 144344323031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70904505841 + 59418937600 = 266279^2 + 243760^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130323443441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130323443398 and 130323443407.
It is not a weakly prime, because it can be changed into another prime (130323443491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65161721720 + 65161721721.
It is an arithmetic number, because the mean of its divisors is an integer number (65161721721).
Almost surely, 2130323443441 is an apocalyptic number.
It is an amenable number.
130323443441 is a deficient number, since it is larger than the sum of its proper divisors (1).
130323443441 is an equidigital number, since it uses as much as digits as its factorization.
130323443441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 130323443441 its reverse (144344323031), we get a palindrome (274667766472).
The spelling of 130323443441 in words is "one hundred thirty billion, three hundred twenty-three million, four hundred forty-three thousand, four hundred forty-one".
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