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130323443441 is a prime number
BaseRepresentation
bin111100101011111100…
…0011110111011110001
3110110101110112212121112
41321113320132323301
54113400300142231
6135511511403105
712262351664102
oct1712770367361
9413343485545
10130323443441
11502a7205a64
1221311083495
13c39bbc0199
1464444223a9
1535cb45392b
hex1e57e1eef1

130323443441 has 2 divisors, whose sum is σ = 130323443442. Its totient is φ = 130323443440.

The previous prime is 130323443429. The next prime is 130323443491. The reversal of 130323443441 is 144344323031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70904505841 + 59418937600 = 266279^2 + 243760^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130323443441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130323443398 and 130323443407.

It is not a weakly prime, because it can be changed into another prime (130323443491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65161721720 + 65161721721.

It is an arithmetic number, because the mean of its divisors is an integer number (65161721721).

Almost surely, 2130323443441 is an apocalyptic number.

It is an amenable number.

130323443441 is a deficient number, since it is larger than the sum of its proper divisors (1).

130323443441 is an equidigital number, since it uses as much as digits as its factorization.

130323443441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 130323443441 its reverse (144344323031), we get a palindrome (274667766472).

The spelling of 130323443441 in words is "one hundred thirty billion, three hundred twenty-three million, four hundred forty-three thousand, four hundred forty-one".