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130325252081 is a prime number
BaseRepresentation
bin111100101011111111…
…1011000011111110001
3110110101120221202121012
41321113333120133301
54113401231031311
6135512014240305
712262403236103
oct1712777303761
9413346852535
10130325252081
11502a8230902
12213117b6095
13c39c3a449b
146444773573
1535cb6ae78b
hex1e57fd87f1

130325252081 has 2 divisors, whose sum is σ = 130325252082. Its totient is φ = 130325252080.

The previous prime is 130325252039. The next prime is 130325252089. The reversal of 130325252081 is 180252523031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79614265600 + 50710986481 = 282160^2 + 225191^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130325252081 is a prime.

It is a super-2 number, since 2×1303252520812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130325252089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65162626040 + 65162626041.

It is an arithmetic number, because the mean of its divisors is an integer number (65162626041).

Almost surely, 2130325252081 is an apocalyptic number.

It is an amenable number.

130325252081 is a deficient number, since it is larger than the sum of its proper divisors (1).

130325252081 is an equidigital number, since it uses as much as digits as its factorization.

130325252081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 130325252081 in words is "one hundred thirty billion, three hundred twenty-five million, two hundred fifty-two thousand, eighty-one".