Base | Representation |
---|---|
bin | 11101101000011110111011… |
… | …010000110100110000101100 |
3 | 122002102222110122002210210210 |
4 | 131220132323100310300230 |
5 | 114040222241102143312 |
6 | 1141102344311302420 |
7 | 36310460164451433 |
oct | 3550367320646054 |
9 | 562388418083723 |
10 | 130325334412332 |
11 | 38586733779484 |
12 | 12749b0a97aa10 |
13 | 579481aca6507 |
14 | 2427acbc5811a |
15 | 10100dae84e3c |
hex | 7687bb434c2c |
130325334412332 has 24 divisors (see below), whose sum is σ = 304162530616000. Its totient is φ = 43431766186896.
The previous prime is 130325334412241. The next prime is 130325334412333. The reversal of 130325334412332 is 233214433523031.
It is not an unprimeable number, because it can be changed into a prime (130325334412333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1251439582 + ... + 1251543717.
Almost surely, 2130325334412332 is an apocalyptic number.
130325334412332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
130325334412332 is an abundant number, since it is smaller than the sum of its proper divisors (173837196203668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130325334412332 is a wasteful number, since it uses less digits than its factorization.
130325334412332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2502987645 (or 2502987643 counting only the distinct ones).
The product of its (nonzero) digits is 466560, while the sum is 39.
Adding to 130325334412332 its reverse (233214433523031), we get a palindrome (363539767935363).
The spelling of 130325334412332 in words is "one hundred thirty trillion, three hundred twenty-five billion, three hundred thirty-four million, four hundred twelve thousand, three hundred thirty-two".
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