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13033041334249 is a prime number
BaseRepresentation
bin1011110110100111110111…
…0011001000111111101001
31201010221120001121012220211
42331221331303020333221
53202013132040143444
643415144015021121
72513414625326056
oct275517563107751
951127501535824
1013033041334249
114175311076202
121565a8320a7a1
1373701a177981
14330b3435602d
151790452bbc34
hexbda7dcc8fe9

13033041334249 has 2 divisors, whose sum is σ = 13033041334250. Its totient is φ = 13033041334248.

The previous prime is 13033041334211. The next prime is 13033041334259. The reversal of 13033041334249 is 94243314033031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11035398309849 + 1997643024400 = 3321957^2 + 1413380^2 .

It is a cyclic number.

It is not a de Polignac number, because 13033041334249 - 213 = 13033041326057 is a prime.

It is not a weakly prime, because it can be changed into another prime (13033041334259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516520667124 + 6516520667125.

It is an arithmetic number, because the mean of its divisors is an integer number (6516520667125).

Almost surely, 213033041334249 is an apocalyptic number.

It is an amenable number.

13033041334249 is a deficient number, since it is larger than the sum of its proper divisors (1).

13033041334249 is an equidigital number, since it uses as much as digits as its factorization.

13033041334249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 279936, while the sum is 40.

The spelling of 13033041334249 in words is "thirteen trillion, thirty-three billion, forty-one million, three hundred thirty-four thousand, two hundred forty-nine".