Base | Representation |
---|---|
bin | 111100101100001100… |
… | …1100101100011101011 |
3 | 110110102001212202102120 |
4 | 1321120121211203223 |
5 | 4113410010340243 |
6 | 135512421402323 |
7 | 12262515516045 |
oct | 1713031454353 |
9 | 413361782376 |
10 | 130332121323 |
11 | 503010a2868 |
12 | 21313b693a3 |
13 | c3a093b021 |
14 | 6445640a95 |
15 | 35cc0b9c83 |
hex | 1e586658eb |
130332121323 has 4 divisors (see below), whose sum is σ = 173776161768. Its totient is φ = 86888080880.
The previous prime is 130332121321. The next prime is 130332121331. The reversal of 130332121323 is 323121233031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130332121323 - 21 = 130332121321 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130332121293 and 130332121302.
It is not an unprimeable number, because it can be changed into a prime (130332121321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21722020218 + ... + 21722020223.
It is an arithmetic number, because the mean of its divisors is an integer number (43444040442).
Almost surely, 2130332121323 is an apocalyptic number.
130332121323 is a deficient number, since it is larger than the sum of its proper divisors (43444040445).
130332121323 is an equidigital number, since it uses as much as digits as its factorization.
130332121323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43444040444.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 130332121323 its reverse (323121233031), we get a palindrome (453453354354).
The spelling of 130332121323 in words is "one hundred thirty billion, three hundred thirty-two million, one hundred twenty-one thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •