1303404121153 has 4 divisors (see below), whose sum is σ = 1303915062208. Its totient is φ = 1302893180100.

The previous prime is 1303404121139. The next prime is 1303404121171. The reversal of 1303404121153 is 3511214043031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1303404121153 - 2¹³ = 1303404112961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1303404124153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255466701 + ... + 255471802.

It is an arithmetic number, because the mean of its divisors is an integer number (325978765552).

Almost surely, 2^{1303404121153} is an apocalyptic number.

It is an amenable number.

1303404121153 is a deficient number, since it is larger than the sum of its proper divisors (510941055).

1303404121153 is an equidigital number, since it uses as much as digits as its factorization.

1303404121153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 510941054.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 1303404121153 its reverse (3511214043031), we get a palindrome (4814618164184).

The spelling of 1303404121153 in words is "one trillion, three hundred three billion, four hundred four million, one hundred twenty-one thousand, one hundred fifty-three".