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13034114820451 is a prime number
BaseRepresentation
bin1011110110101011110111…
…0010001010100101100011
31201011001022212112222011001
42331222331302022211203
53202022331343223301
643415442323332431
72513453341653334
oct275527562124543
951131285488131
1013034114820451
11417581202128a
121566122821117
1373715b6a43ca
14330bd6b5228b
151790a9666c01
hexbdabdc8a963

13034114820451 has 2 divisors, whose sum is σ = 13034114820452. Its totient is φ = 13034114820450.

The previous prime is 13034114820317. The next prime is 13034114820523. The reversal of 13034114820451 is 15402841143031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13034114820451 - 219 = 13034114296163 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13034114820451.

It is not a weakly prime, because it can be changed into another prime (13034114820151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6517057410225 + 6517057410226.

It is an arithmetic number, because the mean of its divisors is an integer number (6517057410226).

Almost surely, 213034114820451 is an apocalyptic number.

13034114820451 is a deficient number, since it is larger than the sum of its proper divisors (1).

13034114820451 is an equidigital number, since it uses as much as digits as its factorization.

13034114820451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46080, while the sum is 37.

Adding to 13034114820451 its reverse (15402841143031), we get a palindrome (28436955963482).

The spelling of 13034114820451 in words is "thirteen trillion, thirty-four billion, one hundred fourteen million, eight hundred twenty thousand, four hundred fifty-one".