Base | Representation |
---|---|
bin | 11101101000101101101101… |
… | …100101001011101111001011 |
3 | 122002111111110002200210202111 |
4 | 131220231231211023233023 |
5 | 114041002300003330114 |
6 | 1141113531541443151 |
7 | 36311561500260406 |
oct | 3550555545135713 |
9 | 562444402623674 |
10 | 130341210995659 |
11 | 38592440689524 |
12 | 12750bbba104b7 |
13 | 579617b30a611 |
14 | 2428796660d3d |
15 | 1010719becbc4 |
hex | 768b6d94bbcb |
130341210995659 has 2 divisors, whose sum is σ = 130341210995660. Its totient is φ = 130341210995658.
The previous prime is 130341210995651. The next prime is 130341210995683. The reversal of 130341210995659 is 956599012143031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130341210995659 - 23 = 130341210995651 is a prime.
It is a super-2 number, since 2×1303412109956592 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130341210995651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65170605497829 + 65170605497830.
It is an arithmetic number, because the mean of its divisors is an integer number (65170605497830).
Almost surely, 2130341210995659 is an apocalyptic number.
130341210995659 is a deficient number, since it is larger than the sum of its proper divisors (1).
130341210995659 is an equidigital number, since it uses as much as digits as its factorization.
130341210995659 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7873200, while the sum is 58.
The spelling of 130341210995659 in words is "one hundred thirty trillion, three hundred forty-one billion, two hundred ten million, nine hundred ninety-five thousand, six hundred fifty-nine".
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