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1303414142113 is a prime number
BaseRepresentation
bin10010111101111001100…
…010010111010010100001
311121121100011122211202001
4102331321202113102201
5132323343010021423
62434440304324001
7163111550256436
oct22757142272241
94547304584661
101303414142113
11462858337746
1219073a913601
1395bb0532285
144712ab97b8d
1523d88a22cad
hex12f798974a1

1303414142113 has 2 divisors, whose sum is σ = 1303414142114. Its totient is φ = 1303414142112.

The previous prime is 1303414142053. The next prime is 1303414142197. The reversal of 1303414142113 is 3112414143031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1273846307904 + 29567834209 = 1128648^2 + 171953^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1303414142113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1303414146113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651707071056 + 651707071057.

It is an arithmetic number, because the mean of its divisors is an integer number (651707071057).

Almost surely, 21303414142113 is an apocalyptic number.

It is an amenable number.

1303414142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303414142113 is an equidigital number, since it uses as much as digits as its factorization.

1303414142113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1303414142113 its reverse (3112414143031), we get a palindrome (4415828285144).

The spelling of 1303414142113 in words is "one trillion, three hundred three billion, four hundred fourteen million, one hundred forty-two thousand, one hundred thirteen".