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130343440155 = 3511637471679
BaseRepresentation
bin111100101100100010…
…0110000111100011011
3110110102212011210221120
41321121010300330123
54113420410041110
6135513504140323
712263013650415
oct1713104607433
9413385153846
10130343440155
1150307523875
12213179076a3
13c3a30a1c66
146446d499b5
1535cd0a3870
hex1e59130f1b

130343440155 has 16 divisors (see below), whose sum is σ = 208728852480. Its totient is φ = 69456718688.

The previous prime is 130343440153. The next prime is 130343440163. The reversal of 130343440155 is 551044343031.

It is a cyclic number.

It is not a de Polignac number, because 130343440155 - 21 = 130343440153 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130343440153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3718395 + ... + 3753284.

It is an arithmetic number, because the mean of its divisors is an integer number (13045553280).

Almost surely, 2130343440155 is an apocalyptic number.

130343440155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130343440155 is a deficient number, since it is larger than the sum of its proper divisors (78385412325).

130343440155 is a wasteful number, since it uses less digits than its factorization.

130343440155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7472850.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 130343440155 its reverse (551044343031), we get a palindrome (681387783186).

The spelling of 130343440155 in words is "one hundred thirty billion, three hundred forty-three million, four hundred forty thousand, one hundred fifty-five".

Divisors: 1 3 5 15 1163 3489 5815 17445 7471679 22415037 37358395 112075185 8689562677 26068688031 43447813385 130343440155