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130344313351 = 7531129311189
BaseRepresentation
bin111100101100100100…
…0000110001000000111
3110110102220211011202011
41321121020012020013
54113421121011401
6135513534555051
712263024245240
oct1713110061007
9413386734664
10130344313351
1150307a6a91a
1221318068a87
13c3a3319545
1464470d5cc7
1535cd1c7451
hex1e59206207

130344313351 has 16 divisors (see below), whose sum is σ = 151910510400. Its totient is φ = 109518259968.

The previous prime is 130344313349. The next prime is 130344313381. The reversal of 130344313351 is 153313443031.

It is a cyclic number.

It is not a de Polignac number, because 130344313351 - 21 = 130344313349 is a prime.

It is a super-3 number, since 3×1303443133513 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130344313321) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 263265 + ... + 574453.

It is an arithmetic number, because the mean of its divisors is an integer number (9494406900).

Almost surely, 2130344313351 is an apocalyptic number.

130344313351 is a deficient number, since it is larger than the sum of its proper divisors (21566197049).

130344313351 is a wasteful number, since it uses less digits than its factorization.

130344313351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312378.

The product of its (nonzero) digits is 19440, while the sum is 31.

Adding to 130344313351 its reverse (153313443031), we get a palindrome (283657756382).

The spelling of 130344313351 in words is "one hundred thirty billion, three hundred forty-four million, three hundred thirteen thousand, three hundred fifty-one".

Divisors: 1 7 53 371 1129 7903 59837 311189 418859 2178323 16493017 115451119 351332381 2459326667 18620616193 130344313351