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13034616125441 is a prime number
BaseRepresentation
bin1011110110101101101110…
…1010011111100000000001
31201011002121210211220022112
42331223123222133200001
53202024343212003231
643420004152145105
72513501636664041
oct275533352374001
951132553756275
1013034616125441
114175a49a9a129
121566242698195
1373720b4c5491
14330c43567721
151790d868b92b
hexbdadba9f801

13034616125441 has 2 divisors, whose sum is σ = 13034616125442. Its totient is φ = 13034616125440.

The previous prime is 13034616125437. The next prime is 13034616125549. The reversal of 13034616125441 is 14452161643031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9032855931841 + 4001760193600 = 3005471^2 + 2000440^2 .

It is a cyclic number.

It is not a de Polignac number, because 13034616125441 - 22 = 13034616125437 is a prime.

It is not a weakly prime, because it can be changed into another prime (13034616125411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6517308062720 + 6517308062721.

It is an arithmetic number, because the mean of its divisors is an integer number (6517308062721).

Almost surely, 213034616125441 is an apocalyptic number.

It is an amenable number.

13034616125441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13034616125441 is an equidigital number, since it uses as much as digits as its factorization.

13034616125441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 41.

Adding to 13034616125441 its reverse (14452161643031), we get a palindrome (27486777768472).

The spelling of 13034616125441 in words is "thirteen trillion, thirty-four billion, six hundred sixteen million, one hundred twenty-five thousand, four hundred forty-one".