Base | Representation |
---|---|
bin | 11000010001111010… |
… | …00101011000010001 |
3 | 1020122102220100002201 |
4 | 30020331011120101 |
5 | 203143443214213 |
6 | 5553244043201 |
7 | 641010540361 |
oct | 141075053021 |
9 | 36572810081 |
10 | 13035132433 |
11 | 5589aa0a24 |
12 | 2639533501 |
13 | 12c9752b1b |
14 | 8b92b29a1 |
15 | 5145916dd |
hex | 308f45611 |
13035132433 has 4 divisors (see below), whose sum is σ = 13455620608. Its totient is φ = 12614644260.
The previous prime is 13035132431. The next prime is 13035132463. The reversal of 13035132433 is 33423153031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33423153031 = 1049 ⋅31861919.
It is a cyclic number.
It is not a de Polignac number, because 13035132433 - 21 = 13035132431 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13035132431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 210244041 + ... + 210244102.
It is an arithmetic number, because the mean of its divisors is an integer number (3363905152).
Almost surely, 213035132433 is an apocalyptic number.
It is an amenable number.
13035132433 is a deficient number, since it is larger than the sum of its proper divisors (420488175).
13035132433 is an equidigital number, since it uses as much as digits as its factorization.
13035132433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 420488174.
The product of its (nonzero) digits is 9720, while the sum is 28.
Adding to 13035132433 its reverse (33423153031), we get a palindrome (46458285464).
The spelling of 13035132433 in words is "thirteen billion, thirty-five million, one hundred thirty-two thousand, four hundred thirty-three".
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