Base | Representation |
---|---|
bin | 1011110110110000011011… |
… | …0100011001101100101011 |
3 | 1201011011111021012211020121 |
4 | 2331230012310121230223 |
5 | 3202032334034042103 |
6 | 43420204054304111 |
7 | 2513525611020424 |
oct | 275540664315453 |
9 | 51134437184217 |
10 | 13035340143403 |
11 | 4176290753586 |
12 | 1566405058037 |
13 | 7372c54c3a86 |
14 | 330cb179464b |
15 | 17912c0056bd |
hex | bdb06d19b2b |
13035340143403 has 2 divisors, whose sum is σ = 13035340143404. Its totient is φ = 13035340143402.
The previous prime is 13035340143379. The next prime is 13035340143439. The reversal of 13035340143403 is 30434104353031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13035340143403 - 233 = 13026750208811 is a prime.
It is not a weakly prime, because it can be changed into another prime (13035340143443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6517670071701 + 6517670071702.
It is an arithmetic number, because the mean of its divisors is an integer number (6517670071702).
Almost surely, 213035340143403 is an apocalyptic number.
13035340143403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13035340143403 is an equidigital number, since it uses as much as digits as its factorization.
13035340143403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 34.
Adding to 13035340143403 its reverse (30434104353031), we get a palindrome (43469444496434).
The spelling of 13035340143403 in words is "thirteen trillion, thirty-five billion, three hundred forty million, one hundred forty-three thousand, four hundred three".
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