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13037234203057 is a prime number
BaseRepresentation
bin1011110110110111011110…
…1101101010100110110001
31201011100101021020000122011
42331231313231222212301
53202100223423444212
643421120034442521
72513623550166301
oct275556755524661
951140337200564
1013037234203057
114177072911639
121566853433441
13737537a2782c
14331011153601
151791dd43d4a7
hexbdb77b6a9b1

13037234203057 has 2 divisors, whose sum is σ = 13037234203058. Its totient is φ = 13037234203056.

The previous prime is 13037234203039. The next prime is 13037234203087. The reversal of 13037234203057 is 75030243273031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8471644750881 + 4565589452176 = 2910609^2 + 2136724^2 .

It is a cyclic number.

It is not a de Polignac number, because 13037234203057 - 231 = 13035086719409 is a prime.

It is not a weakly prime, because it can be changed into another prime (13037234203027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6518617101528 + 6518617101529.

It is an arithmetic number, because the mean of its divisors is an integer number (6518617101529).

Almost surely, 213037234203057 is an apocalyptic number.

It is an amenable number.

13037234203057 is a deficient number, since it is larger than the sum of its proper divisors (1).

13037234203057 is an equidigital number, since it uses as much as digits as its factorization.

13037234203057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 317520, while the sum is 40.

Adding to 13037234203057 its reverse (75030243273031), we get a palindrome (88067477476088).

The spelling of 13037234203057 in words is "thirteen trillion, thirty-seven billion, two hundred thirty-four million, two hundred three thousand, fifty-seven".