Base | Representation |
---|---|
bin | 11000010010100000… |
… | …00010011010110001 |
3 | 1020122210020202202020 |
4 | 30021100002122301 |
5 | 203201231213131 |
6 | 5553542342053 |
7 | 641101013202 |
oct | 141120023261 |
9 | 36583222666 |
10 | 13040101041 |
11 | 5591884a10 |
12 | 263b12a929 |
13 | 12ca7a2526 |
14 | 8b9c075a9 |
15 | 514c23996 |
hex | 3094026b1 |
13040101041 has 16 divisors (see below), whose sum is σ = 18992380608. Its totient is φ = 7892691200.
The previous prime is 13040101027. The next prime is 13040101043. The reversal of 13040101041 is 14010104031.
It is a cyclic number.
It is not a de Polignac number, because 13040101041 - 26 = 13040100977 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13040101041.
It is not an unprimeable number, because it can be changed into a prime (13040101043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 234516 + ... + 284741.
It is an arithmetic number, because the mean of its divisors is an integer number (1187023788).
Almost surely, 213040101041 is an apocalyptic number.
13040101041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13040101041 is a deficient number, since it is larger than the sum of its proper divisors (5952279567).
13040101041 is a wasteful number, since it uses less digits than its factorization.
13040101041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 520032.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 13040101041 its reverse (14010104031), we get a palindrome (27050205072).
The spelling of 13040101041 in words is "thirteen billion, forty million, one hundred one thousand, forty-one".
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