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13040110432457 is a prime number
BaseRepresentation
bin1011110111000010001100…
…1001100111000011001001
31201011121210201100121121222
42331300203021213003021
53202122121232314312
643422313302211425
72514055043554613
oct275604311470311
951147721317558
1013040110432457
114178309425329
121567316723b75
137378a5894b14
1433120513bdb3
1517930abd4672
hexbdc232670c9

13040110432457 has 2 divisors, whose sum is σ = 13040110432458. Its totient is φ = 13040110432456.

The previous prime is 13040110432409. The next prime is 13040110432477. The reversal of 13040110432457 is 75423401104031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9767850126736 + 3272260305721 = 3125356^2 + 1808939^2 .

It is a cyclic number.

It is not a de Polignac number, because 13040110432457 - 228 = 13039841997001 is a prime.

It is not a weakly prime, because it can be changed into another prime (13040110432477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520055216228 + 6520055216229.

It is an arithmetic number, because the mean of its divisors is an integer number (6520055216229).

Almost surely, 213040110432457 is an apocalyptic number.

It is an amenable number.

13040110432457 is a deficient number, since it is larger than the sum of its proper divisors (1).

13040110432457 is an equidigital number, since it uses as much as digits as its factorization.

13040110432457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40320, while the sum is 35.

Adding to 13040110432457 its reverse (75423401104031), we get a palindrome (88463511536488).

The spelling of 13040110432457 in words is "thirteen trillion, forty billion, one hundred ten million, four hundred thirty-two thousand, four hundred fifty-seven".