13040121121 has 4 divisors (see below), whose sum is σ = 13489780500. Its totient is φ = 12590461744.

The previous prime is 13040121103. The next prime is 13040121161. The reversal of 13040121121 is 12112104031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 12112104031 = 37 ⋅327354163.

It can be written as a sum of positive squares in 2 ways, for example, as 9188181025 + 3851940096 = 95855^2 + 62064^2 .

It is a cyclic number.

It is not a de Polignac number, because 13040121121 - 2¹⁹ = 13039596833 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13040121095 and 13040121104.

It is not an unprimeable number, because it can be changed into a prime (13040121161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224829646 + ... + 224829703.

It is an arithmetic number, because the mean of its divisors is an integer number (3372445125).

Almost surely, 2^13040121121 is an apocalyptic number.

It is an amenable number.

13040121121 is a deficient number, since it is larger than the sum of its proper divisors (449659379).

13040121121 is an equidigital number, since it uses as much as digits as its factorization.

13040121121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 449659378.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13040121121 its reverse (12112104031), we get a palindrome (25152225152).

The spelling of 13040121121 in words is "thirteen billion, forty million, one hundred twenty-one thousand, one hundred twenty-one".