13040125131 has 16 divisors (see below), whose sum is σ = 18969920640. Its totient is φ = 7902078720.

The previous prime is 13040125099. The next prime is 13040125139. The reversal of 13040125131 is 13152104031.

It is not a de Polignac number, because 13040125131 - 2⁵ = 13040125099 is a prime.

It is a super-2 number, since 2×13040125131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13040125098 and 13040125107.

It is not an unprimeable number, because it can be changed into a prime (13040125139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 289851 + ... + 331803.

It is an arithmetic number, because the mean of its divisors is an integer number (1185620040).

Almost surely, 2^13040125131 is an apocalyptic number.

13040125131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13040125131 is a deficient number, since it is larger than the sum of its proper divisors (5929795509).

13040125131 is a wasteful number, since it uses less digits than its factorization.

13040125131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51386.

The product of its (nonzero) digits is 360, while the sum is 21.

Adding to 13040125131 its reverse (13152104031), we get a palindrome (26192229162).

The spelling of 13040125131 in words is "thirteen billion, forty million, one hundred twenty-five thousand, one hundred thirty-one".