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130402572257 is a prime number
BaseRepresentation
bin111100101110010011…
…0010101011111100001
3110110120222110000221102
41321130212111133201
54114031024303012
6135523415404145
712264332401256
oct1713446253741
9413528400842
10130402572257
1150337941681
1221333683655
13c3b2406b79
146450b3d42d
1535d33842c2
hex1e5c9957e1

130402572257 has 2 divisors, whose sum is σ = 130402572258. Its totient is φ = 130402572256.

The previous prime is 130402572239. The next prime is 130402572281. The reversal of 130402572257 is 752275204031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130072750336 + 329821921 = 360656^2 + 18161^2 .

It is a cyclic number.

It is not a de Polignac number, because 130402572257 - 26 = 130402572193 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130402572257.

It is not a weakly prime, because it can be changed into another prime (130402512257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65201286128 + 65201286129.

It is an arithmetic number, because the mean of its divisors is an integer number (65201286129).

Almost surely, 2130402572257 is an apocalyptic number.

It is an amenable number.

130402572257 is a deficient number, since it is larger than the sum of its proper divisors (1).

130402572257 is an equidigital number, since it uses as much as digits as its factorization.

130402572257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 117600, while the sum is 38.

Adding to 130402572257 its reverse (752275204031), we get a palindrome (882677776288).

The spelling of 130402572257 in words is "one hundred thirty billion, four hundred two million, five hundred seventy-two thousand, two hundred fifty-seven".