Base | Representation |
---|---|
bin | 10010111110011110011… |
… | …110111100110001100011 |
3 | 11121122221101001002111012 |
4 | 102332132132330301203 |
5 | 132331130201112232 |
6 | 2435022010211135 |
7 | 163133115101234 |
oct | 22763636746143 |
9 | 4548841032435 |
10 | 1304034004067 |
11 | 463046221153 |
12 | 190892423aab |
13 | 95c7ba934b2 |
14 | 4718923108b |
15 | 23dc31659b2 |
hex | 12f9e7bcc63 |
1304034004067 has 4 divisors (see below), whose sum is σ = 1307146257480. Its totient is φ = 1300921750656.
The previous prime is 1304034004061. The next prime is 1304034004069. The reversal of 1304034004067 is 7604004304031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1304034004067 - 212 = 1304033999971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1304034004061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1556126078 + ... + 1556126915.
It is an arithmetic number, because the mean of its divisors is an integer number (326786564370).
Almost surely, 21304034004067 is an apocalyptic number.
1304034004067 is a deficient number, since it is larger than the sum of its proper divisors (3112253413).
1304034004067 is an equidigital number, since it uses as much as digits as its factorization.
1304034004067 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3112253412.
The product of its (nonzero) digits is 24192, while the sum is 32.
Adding to 1304034004067 its reverse (7604004304031), we get a palindrome (8908038308098).
The spelling of 1304034004067 in words is "one trillion, three hundred four billion, thirty-four million, four thousand, sixty-seven".
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