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1304034004067 = 4193112252993
BaseRepresentation
bin10010111110011110011…
…110111100110001100011
311121122221101001002111012
4102332132132330301203
5132331130201112232
62435022010211135
7163133115101234
oct22763636746143
94548841032435
101304034004067
11463046221153
12190892423aab
1395c7ba934b2
144718923108b
1523dc31659b2
hex12f9e7bcc63

1304034004067 has 4 divisors (see below), whose sum is σ = 1307146257480. Its totient is φ = 1300921750656.

The previous prime is 1304034004061. The next prime is 1304034004069. The reversal of 1304034004067 is 7604004304031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1304034004067 - 212 = 1304033999971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1304034004061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1556126078 + ... + 1556126915.

It is an arithmetic number, because the mean of its divisors is an integer number (326786564370).

Almost surely, 21304034004067 is an apocalyptic number.

1304034004067 is a deficient number, since it is larger than the sum of its proper divisors (3112253413).

1304034004067 is an equidigital number, since it uses as much as digits as its factorization.

1304034004067 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3112253412.

The product of its (nonzero) digits is 24192, while the sum is 32.

Adding to 1304034004067 its reverse (7604004304031), we get a palindrome (8908038308098).

The spelling of 1304034004067 in words is "one trillion, three hundred four billion, thirty-four million, four thousand, sixty-seven".

Divisors: 1 419 3112252993 1304034004067