Base | Representation |
---|---|
bin | 1011110111000011001010… |
… | …0001111000110001000011 |
3 | 1201011122110200212111122012 |
4 | 2331300302201320301003 |
5 | 3202123133311022343 |
6 | 43422355040403135 |
7 | 2514064325661251 |
oct | 275606241706103 |
9 | 51148420774565 |
10 | 13040368454723 |
11 | 4178431038275 |
12 | 15673890164ab |
13 | 737917185b0c |
14 | 33122b5055d1 |
15 | 1793236a0718 |
hex | bdc32878c43 |
13040368454723 has 2 divisors, whose sum is σ = 13040368454724. Its totient is φ = 13040368454722.
The previous prime is 13040368454699. The next prime is 13040368454741. The reversal of 13040368454723 is 32745486304031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13040368454723 - 210 = 13040368453699 is a prime.
It is not a weakly prime, because it can be changed into another prime (13040368054723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520184227361 + 6520184227362.
It is an arithmetic number, because the mean of its divisors is an integer number (6520184227362).
Almost surely, 213040368454723 is an apocalyptic number.
13040368454723 is a deficient number, since it is larger than the sum of its proper divisors (1).
13040368454723 is an equidigital number, since it uses as much as digits as its factorization.
13040368454723 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5806080, while the sum is 50.
The spelling of 13040368454723 in words is "thirteen trillion, forty billion, three hundred sixty-eight million, four hundred fifty-four thousand, seven hundred twenty-three".
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