Base | Representation |
---|---|
bin | 111100101110010110… |
… | …1011110000001010001 |
3 | 110110121002222001000022 |
4 | 1321130231132001101 |
5 | 4114032014122233 |
6 | 135523523433225 |
7 | 12264354320054 |
oct | 1713455360121 |
9 | 413532861008 |
10 | 130404442193 |
11 | 503389a9583 |
12 | 21334225815 |
13 | c3b291003c |
14 | 64510a8a9b |
15 | 35d3603398 |
hex | 1e5cb5e051 |
130404442193 has 2 divisors, whose sum is σ = 130404442194. Its totient is φ = 130404442192.
The previous prime is 130404442123. The next prime is 130404442199. The reversal of 130404442193 is 391244404031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101564590864 + 28839851329 = 318692^2 + 169823^2 .
It is a cyclic number.
It is not a de Polignac number, because 130404442193 - 216 = 130404376657 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (130404442199) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65202221096 + 65202221097.
It is an arithmetic number, because the mean of its divisors is an integer number (65202221097).
Almost surely, 2130404442193 is an apocalyptic number.
It is an amenable number.
130404442193 is a deficient number, since it is larger than the sum of its proper divisors (1).
130404442193 is an equidigital number, since it uses as much as digits as its factorization.
130404442193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 130404442193 in words is "one hundred thirty billion, four hundred four million, four hundred forty-two thousand, one hundred ninety-three".
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