130405040323 has 4 divisors (see below), whose sum is σ = 131749422280. Its totient is φ = 129060658368.

The previous prime is 130405040309. The next prime is 130405040347. The reversal of 130405040323 is 323040504031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 323040504031 = 7 ⋅46148643433.

It is a cyclic number.

It is not a de Polignac number, because 130405040323 - 2⁹ = 130405039811 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130405040383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 672190833 + ... + 672191026.

It is an arithmetic number, because the mean of its divisors is an integer number (32937355570).

Almost surely, 2^130405040323 is an apocalyptic number.

130405040323 is a deficient number, since it is larger than the sum of its proper divisors (1344381957).

130405040323 is an equidigital number, since it uses as much as digits as its factorization.

130405040323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1344381956.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 130405040323 its reverse (323040504031), we get a palindrome (453445544354).

The spelling of 130405040323 in words is "one hundred thirty billion, four hundred five million, forty thousand, three hundred twenty-three".