13040535367441 has 4 divisors (see below), whose sum is σ = 13043157639732. Its totient is φ = 13037913095152.

The previous prime is 13040535367399. The next prime is 13040535367463. The reversal of 13040535367441 is 14476353504031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6531709829841 + 6508825537600 = 2555721^2 + 2551240^2 .

It is a cyclic number.

It is not a de Polignac number, because 13040535367441 - 2¹⁷ = 13040535236369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13040535367391 and 13040535367400.

It is not an unprimeable number, because it can be changed into a prime (13040535367481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311128686 + ... + 1311138631.

It is an arithmetic number, because the mean of its divisors is an integer number (3260789409933).

Almost surely, 2^{13040535367441} is an apocalyptic number.

It is an amenable number.

13040535367441 is a deficient number, since it is larger than the sum of its proper divisors (2622272291).

13040535367441 is an equidigital number, since it uses as much as digits as its factorization.

13040535367441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2622272290.

The product of its (nonzero) digits is 1814400, while the sum is 46.

The spelling of 13040535367441 in words is "thirteen trillion, forty billion, five hundred thirty-five million, three hundred sixty-seven thousand, four hundred forty-one".