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13041020441 = 76991693859
BaseRepresentation
bin11000010010100111…
…00010111000011001
31020122211222110221002
430021103202320121
5203202000123231
65554014154345
7641111562521
oct141123427031
936584873832
1013041020441
115592352749
12263b4b29b5
1312caa34b57
148b9da6681
15514d560cb
hex3094e2e19

13041020441 has 4 divisors (see below), whose sum is σ = 13042722000. Its totient is φ = 13039318884.

The previous prime is 13041020431. The next prime is 13041020459. The reversal of 13041020441 is 14402014031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14402014031 = 77797185123.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13041020441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13041020431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 839231 + ... + 854628.

It is an arithmetic number, because the mean of its divisors is an integer number (3260680500).

Almost surely, 213041020441 is an apocalyptic number.

It is an amenable number.

13041020441 is a deficient number, since it is larger than the sum of its proper divisors (1701559).

13041020441 is an equidigital number, since it uses as much as digits as its factorization.

13041020441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1701558.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 13041020441 its reverse (14402014031), we get a palindrome (27443034472).

The spelling of 13041020441 in words is "thirteen billion, forty-one million, twenty thousand, four hundred forty-one".

Divisors: 1 7699 1693859 13041020441