Base | Representation |
---|---|
bin | 11101101001101110110101… |
… | …001000110101110011110110 |
3 | 122002202011220221112011002202 |
4 | 131221232311020311303312 |
5 | 114043123444014031402 |
6 | 1141210014014104502 |
7 | 36316615253441606 |
oct | 3551566510656366 |
9 | 562664827464082 |
10 | 130411131002102 |
11 | 3860a060704215 |
12 | 12762673aab132 |
13 | 579c941cc77b2 |
14 | 242bd0a7b2c06 |
15 | 101245d2abb02 |
hex | 769bb5235cf6 |
130411131002102 has 32 divisors (see below), whose sum is σ = 199509225737760. Its totient is φ = 63914491294720.
The previous prime is 130411131002093. The next prime is 130411131002137. The reversal of 130411131002102 is 201200131114031.
It is a super-3 number, since 3×1304111310021023 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 668907428 + ... + 669102360.
It is an arithmetic number, because the mean of its divisors is an integer number (6234663304305).
Almost surely, 2130411131002102 is an apocalyptic number.
130411131002102 is a deficient number, since it is larger than the sum of its proper divisors (69098094735658).
130411131002102 is a wasteful number, since it uses less digits than its factorization.
130411131002102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211408.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 130411131002102 its reverse (201200131114031), we get a palindrome (331611262116133).
The spelling of 130411131002102 in words is "one hundred thirty trillion, four hundred eleven billion, one hundred thirty-one million, two thousand, one hundred two".
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