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130411141561 is a prime number
BaseRepresentation
bin111100101110100011…
…1000001100110111001
3110110121120120101211001
41321131013001212321
54114040223012221
6135524323205001
712264465261541
oct1713507014671
9413546511731
10130411141561
1150341764948
1221336516761
13c3b411746c
146451d30321
1535d3ec8391
hex1e5d1c19b9

130411141561 has 2 divisors, whose sum is σ = 130411141562. Its totient is φ = 130411141560.

The previous prime is 130411141541. The next prime is 130411141571. The reversal of 130411141561 is 165141114031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111018908025 + 19392233536 = 333195^2 + 139256^2 .

It is a cyclic number.

It is not a de Polignac number, because 130411141561 - 27 = 130411141433 is a prime.

It is not a weakly prime, because it can be changed into another prime (130411141541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205570780 + 65205570781.

It is an arithmetic number, because the mean of its divisors is an integer number (65205570781).

Almost surely, 2130411141561 is an apocalyptic number.

It is an amenable number.

130411141561 is a deficient number, since it is larger than the sum of its proper divisors (1).

130411141561 is an equidigital number, since it uses as much as digits as its factorization.

130411141561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 28.

Adding to 130411141561 its reverse (165141114031), we get a palindrome (295552255592).

The spelling of 130411141561 in words is "one hundred thirty billion, four hundred eleven million, one hundred forty-one thousand, five hundred sixty-one".