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13041144001 = 59221036339
BaseRepresentation
bin11000010010101000…
…00001000011000001
31020122212012202102101
430021110001003001
5203202013102001
65554020550401
7641112615664
oct141124010301
936585182371
1013041144001
115592427566
12263b552401
1312caa79172
148b9dd96db
15514d7ca01
hex3095010c1

13041144001 has 4 divisors (see below), whose sum is σ = 13262180400. Its totient is φ = 12820107604.

The previous prime is 13041143993. The next prime is 13041144041. The reversal of 13041144001 is 10044114031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13041144001 - 23 = 13041143993 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13041144001.

It is not an unprimeable number, because it can be changed into a prime (13041144041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110518111 + ... + 110518228.

It is an arithmetic number, because the mean of its divisors is an integer number (3315545100).

Almost surely, 213041144001 is an apocalyptic number.

It is an amenable number.

13041144001 is a deficient number, since it is larger than the sum of its proper divisors (221036399).

13041144001 is an equidigital number, since it uses as much as digits as its factorization.

13041144001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221036398.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 13041144001 its reverse (10044114031), we get a palindrome (23085258032).

The spelling of 13041144001 in words is "thirteen billion, forty-one million, one hundred forty-four thousand, one".

Divisors: 1 59 221036339 13041144001