Base | Representation |
---|---|
bin | 1011110111000110000011… |
… | …0001001100101000101001 |
3 | 1201011201110202121110210221 |
4 | 2331301200301030220221 |
5 | 3202131230410021301 |
6 | 43423004032010041 |
7 | 2514122465611216 |
oct | 275614061145051 |
9 | 51151422543727 |
10 | 13041144220201 |
11 | 4178799a26369 |
12 | 1567564990921 |
13 | 737a0bb02046 |
14 | 3312a2562b0d |
15 | 17936b83bda1 |
hex | bdc60c4ca29 |
13041144220201 has 4 divisors (see below), whose sum is σ = 13041514038672. Its totient is φ = 13040774401732.
The previous prime is 13041144220199. The next prime is 13041144220231. The reversal of 13041144220201 is 10202244114031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13041144220201 - 21 = 13041144220199 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13041144220231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184856335 + ... + 184926868.
It is an arithmetic number, because the mean of its divisors is an integer number (3260378509668).
Almost surely, 213041144220201 is an apocalyptic number.
It is an amenable number.
13041144220201 is a deficient number, since it is larger than the sum of its proper divisors (369818471).
13041144220201 is an equidigital number, since it uses as much as digits as its factorization.
13041144220201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 369818470.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 13041144220201 its reverse (10202244114031), we get a palindrome (23243388334232).
The spelling of 13041144220201 in words is "thirteen trillion, forty-one billion, one hundred forty-four million, two hundred twenty thousand, two hundred one".
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