Base | Representation |
---|---|
bin | 11101101001101111001101… |
… | …001010001100011010011011 |
3 | 122002202012222000212002000121 |
4 | 131221233031022030122123 |
5 | 114043130310201310021 |
6 | 1141210122012014111 |
7 | 36316631246112022 |
oct | 3551571512143233 |
9 | 562665860762017 |
10 | 130411534010011 |
11 | 3860a248144001 |
12 | 12762766a61337 |
13 | 579c9a7650207 |
14 | 242bd4811b8b9 |
15 | 1012483866741 |
hex | 769bcd28c69b |
130411534010011 has 2 divisors, whose sum is σ = 130411534010012. Its totient is φ = 130411534010010.
The previous prime is 130411534009957. The next prime is 130411534010053. The reversal of 130411534010011 is 110010435114031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130411534010011 is a prime.
It is not a weakly prime, because it can be changed into another prime (130411534010711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205767005005 + 65205767005006.
It is an arithmetic number, because the mean of its divisors is an integer number (65205767005006).
Almost surely, 2130411534010011 is an apocalyptic number.
130411534010011 is a deficient number, since it is larger than the sum of its proper divisors (1).
130411534010011 is an equidigital number, since it uses as much as digits as its factorization.
130411534010011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 130411534010011 its reverse (110010435114031), we get a palindrome (240421969124042).
The spelling of 130411534010011 in words is "one hundred thirty trillion, four hundred eleven billion, five hundred thirty-four million, ten thousand, eleven".
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