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13041210002323 is a prime number
BaseRepresentation
bin1011110111000110010010…
…1100001000101110010011
31201011201122100101112220211
42331301210230020232103
53202131344230033243
643423014341544551
72514124225006636
oct275614454105623
951151570345824
1013041210002323
114178823076458
121567582a15157
13737a1c624a89
143312ab1a7c1d
151793724d2d9d
hexbdc64b08b93

13041210002323 has 2 divisors, whose sum is σ = 13041210002324. Its totient is φ = 13041210002322.

The previous prime is 13041210002291. The next prime is 13041210002377. The reversal of 13041210002323 is 32320001214031.

13041210002323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13041210002323 - 25 = 13041210002291 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13041210002294 and 13041210002303.

It is not a weakly prime, because it can be changed into another prime (13041210072323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520605001161 + 6520605001162.

It is an arithmetic number, because the mean of its divisors is an integer number (6520605001162).

Almost surely, 213041210002323 is an apocalyptic number.

13041210002323 is a deficient number, since it is larger than the sum of its proper divisors (1).

13041210002323 is an equidigital number, since it uses as much as digits as its factorization.

13041210002323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 13041210002323 its reverse (32320001214031), we get a palindrome (45361211216354).

The spelling of 13041210002323 in words is "thirteen trillion, forty-one billion, two hundred ten million, two thousand, three hundred twenty-three".