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1304121010433 = 15119372761553
BaseRepresentation
bin10010111110100011101…
…010110110100100000001
311121200011102202110210012
4102332203222312210001
5132331314434313213
62435034355114305
7163135222455143
oct22764352664401
94550142673705
101304121010433
1146309034833a
121908b75a2995
1395c93b07957
14471969dcc93
1523dcab004a8
hex12fa3ab6901

1304121010433 has 16 divisors (see below), whose sum is σ = 1321395968256. Its totient is φ = 1286978457600.

The previous prime is 1304121010417. The next prime is 1304121010457. The reversal of 1304121010433 is 3340101214031.

It is a cyclic number.

It is not a de Polignac number, because 1304121010433 - 24 = 1304121010417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1304121010399 and 1304121010408.

It is not an unprimeable number, because it can be changed into a prime (1304121010463) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21156185 + ... + 21217737.

It is an arithmetic number, because the mean of its divisors is an integer number (82587248016).

Almost surely, 21304121010433 is an apocalyptic number.

It is an amenable number.

1304121010433 is a deficient number, since it is larger than the sum of its proper divisors (17274957823).

1304121010433 is a wasteful number, since it uses less digits than its factorization.

1304121010433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62624.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1304121010433 its reverse (3340101214031), we get a palindrome (4644222224464).

The spelling of 1304121010433 in words is "one trillion, three hundred four billion, one hundred twenty-one million, ten thousand, four hundred thirty-three".

Divisors: 1 151 193 727 29143 61553 109777 140311 9294503 11879729 21186961 44749031 1793839079 6757103681 8636562983 1304121010433