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130412414545113 = 3227511910720621
BaseRepresentation
bin11101101001110000000001…
…101001001010110011011001
3122002202022020101201220002210
4131221300001221022303121
5114043134111110420423
61141210345224545333
736316662130410531
oct3551600151126331
9562668211656083
10130412414545113
113860a65a191068
1212762971922249
13579cab7bbcbbc
14242bdcd04c4c1
1510124d5ceab93
hex769c01a4acd9

130412414545113 has 8 divisors (see below), whose sum is σ = 173890862366976. Its totient is φ = 86937788210000.

The previous prime is 130412414545079. The next prime is 130412414545117. The reversal of 130412414545113 is 311545414214031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130412414545113 - 214 = 130412414528729 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130412414545117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 955292058 + ... + 955428563.

It is an arithmetic number, because the mean of its divisors is an integer number (21736357795872).

Almost surely, 2130412414545113 is an apocalyptic number.

It is an amenable number.

130412414545113 is a deficient number, since it is larger than the sum of its proper divisors (43478447821863).

130412414545113 is a wasteful number, since it uses less digits than its factorization.

130412414545113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1910743375.

The product of its (nonzero) digits is 115200, while the sum is 39.

Adding to 130412414545113 its reverse (311545414214031), we get a palindrome (441957828759144).

The spelling of 130412414545113 in words is "one hundred thirty trillion, four hundred twelve billion, four hundred fourteen million, five hundred forty-five thousand, one hundred thirteen".

Divisors: 1 3 22751 68253 1910720621 5732161863 43470804848371 130412414545113