Base | Representation |
---|---|
bin | 10010111110100100010… |
… | …101010011110101111011 |
3 | 11121200012012200221020121 |
4 | 102332210111103311323 |
5 | 132331330311443121 |
6 | 2435035433434111 |
7 | 163135416202102 |
oct | 22764425236573 |
9 | 4550165627217 |
10 | 1304132140411 |
11 | 46309665a471 |
12 | 1908bb26b937 |
13 | 95c96203939 |
14 | 47198299039 |
15 | 23dcba9d141 |
hex | 12fa4553d7b |
1304132140411 has 4 divisors (see below), whose sum is σ = 1304181936952. Its totient is φ = 1304082343872.
The previous prime is 1304132140387. The next prime is 1304132140427. The reversal of 1304132140411 is 1140412314031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1304132140411 - 29 = 1304132139899 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1304132140481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24858966 + ... + 24911371.
It is an arithmetic number, because the mean of its divisors is an integer number (326045484238).
Almost surely, 21304132140411 is an apocalyptic number.
1304132140411 is a deficient number, since it is larger than the sum of its proper divisors (49796541).
1304132140411 is an equidigital number, since it uses as much as digits as its factorization.
1304132140411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49796540.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1304132140411 its reverse (1140412314031), we get a palindrome (2444544454442).
The spelling of 1304132140411 in words is "one trillion, three hundred four billion, one hundred thirty-two million, one hundred forty thousand, four hundred eleven".
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