130413341012113 has 4 divisors (see below), whose sum is σ = 130440114439488. Its totient is φ = 130386567584740.

The previous prime is 130413341012081. The next prime is 130413341012117. The reversal of 130413341012113 is 311210143314031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130413341012113 - 2⁵ = 130413341012081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130413341012117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13386706381 + ... + 13386716122.

It is an arithmetic number, because the mean of its divisors is an integer number (32610028609872).

Almost surely, 2^{130413341012113} is an apocalyptic number.

It is an amenable number.

130413341012113 is a deficient number, since it is larger than the sum of its proper divisors (26773427375).

130413341012113 is an equidigital number, since it uses as much as digits as its factorization.

130413341012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26773427374.

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 130413341012113 its reverse (311210143314031), we get a palindrome (441623484326144).

The spelling of 130413341012113 in words is "one hundred thirty trillion, four hundred thirteen billion, three hundred forty-one million, twelve thousand, one hundred thirteen".