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130414430331 = 3238699374441
BaseRepresentation
bin111100101110101001…
…1100100100001111011
3110110121210202111011100
41321131103210201323
54114042043232311
6135524521502443
712264535240023
oct1713523444173
9413553674140
10130414430331
1150343600839
1221337641a23
13c3b49c9393
146452548a83
1535d4427a56
hex1e5d4e487b

130414430331 has 12 divisors (see below), whose sum is σ = 188381770200. Its totient is φ = 86940474720.

The previous prime is 130414430323. The next prime is 130414430371. The reversal of 130414430331 is 133034414031.

It is not a de Polignac number, because 130414430331 - 23 = 130414430323 is a prime.

It is a super-2 number, since 2×1304144303312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130414430295 and 130414430304.

It is not an unprimeable number, because it can be changed into a prime (130414430371) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 161071 + ... + 535511.

It is an arithmetic number, because the mean of its divisors is an integer number (15698480850).

Almost surely, 2130414430331 is an apocalyptic number.

130414430331 is a deficient number, since it is larger than the sum of its proper divisors (57967339869).

130414430331 is a wasteful number, since it uses less digits than its factorization.

130414430331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 413146 (or 413143 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 130414430331 its reverse (133034414031), we get a palindrome (263448844362).

The spelling of 130414430331 in words is "one hundred thirty billion, four hundred fourteen million, four hundred thirty thousand, three hundred thirty-one".

Divisors: 1 3 9 38699 116097 348291 374441 1123323 3369969 14490492259 43471476777 130414430331