Base | Representation |
---|---|
bin | 111100101110101011… |
… | …0100000101110000011 |
3 | 110110121212012122112101 |
4 | 1321131112200232003 |
5 | 4114042242414110 |
6 | 135524550211231 |
7 | 12264544630231 |
oct | 1713526405603 |
9 | 413555178471 |
10 | 130415201155 |
11 | 50343a87988 |
12 | 21337953b17 |
13 | c3b4c091a5 |
14 | 64526a9951 |
15 | 35d452b13a |
hex | 1e5d5a0b83 |
130415201155 has 16 divisors (see below), whose sum is σ = 157289397120. Its totient is φ = 103805350272.
The previous prime is 130415201143. The next prime is 130415201159. The reversal of 130415201155 is 551102514031.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130415201155 is a prime.
It is a super-2 number, since 2×1304152011552 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130415201159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1664317 + ... + 1740913.
It is an arithmetic number, because the mean of its divisors is an integer number (9830587320).
Almost surely, 2130415201155 is an apocalyptic number.
130415201155 is a deficient number, since it is larger than the sum of its proper divisors (26874195965).
130415201155 is a wasteful number, since it uses less digits than its factorization.
130415201155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78318.
The product of its (nonzero) digits is 3000, while the sum is 28.
Adding to 130415201155 its reverse (551102514031), we get a palindrome (681517715186).
The spelling of 130415201155 in words is "one hundred thirty billion, four hundred fifteen million, two hundred one thousand, one hundred fifty-five".
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