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130416554651419 is a prime number
BaseRepresentation
bin11101101001110011111000…
…011010011010111100011011
3122002202200220221002002021101
4131221303320122122330123
5114043221100442321134
61141212312121452231
736320166541626361
oct3551637032327433
9562680827062241
10130416554651419
113861139416a223
1212763728341077
1357a02c785814a
14242c2a2c33631
1510126794e8e14
hex769cf869af1b

130416554651419 has 2 divisors, whose sum is σ = 130416554651420. Its totient is φ = 130416554651418.

The previous prime is 130416554651393. The next prime is 130416554651459. The reversal of 130416554651419 is 914156455614031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130416554651419 - 27 = 130416554651291 is a prime.

It is a super-2 number, since 2×1304165546514192 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130416554651419.

It is not a weakly prime, because it can be changed into another prime (130416554651459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65208277325709 + 65208277325710.

It is an arithmetic number, because the mean of its divisors is an integer number (65208277325710).

Almost surely, 2130416554651419 is an apocalyptic number.

130416554651419 is a deficient number, since it is larger than the sum of its proper divisors (1).

130416554651419 is an equidigital number, since it uses as much as digits as its factorization.

130416554651419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776000, while the sum is 55.

The spelling of 130416554651419 in words is "one hundred thirty trillion, four hundred sixteen billion, five hundred fifty-four million, six hundred fifty-one thousand, four hundred nineteen".