Base | Representation |
---|---|
bin | 10010111110101000011… |
… | …100111001111010001001 |
3 | 11121200101000201120100002 |
4 | 102332220130321322021 |
5 | 132332001004141301 |
6 | 2435050342452345 |
7 | 163140215426156 |
oct | 22765034717211 |
9 | 4550330646302 |
10 | 1304201240201 |
11 | 463121666132 |
12 | 19091a4340b5 |
13 | 95ca76187a2 |
14 | 471a352522d |
15 | 23dd2b9c16b |
hex | 12fa8739e89 |
1304201240201 has 2 divisors, whose sum is σ = 1304201240202. Its totient is φ = 1304201240200.
The previous prime is 1304201240183. The next prime is 1304201240207. The reversal of 1304201240201 is 1020421024031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 881441200201 + 422760040000 = 938851^2 + 650200^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304201240201 - 234 = 1287021371017 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1304201240207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652100620100 + 652100620101.
It is an arithmetic number, because the mean of its divisors is an integer number (652100620101).
Almost surely, 21304201240201 is an apocalyptic number.
It is an amenable number.
1304201240201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304201240201 is an equidigital number, since it uses as much as digits as its factorization.
1304201240201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1304201240201 its reverse (1020421024031), we get a palindrome (2324622264232).
The spelling of 1304201240201 in words is "one trillion, three hundred four billion, two hundred one million, two hundred forty thousand, two hundred one".
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