Base | Representation |
---|---|
bin | 11101101001111010110100… |
… | …010000110000011111001011 |
3 | 122002210102010220002001110121 |
4 | 131221322310100300133023 |
5 | 114043331323301431443 |
6 | 1141215543051124111 |
7 | 36320552222360626 |
oct | 3551726420603713 |
9 | 562712126061417 |
10 | 130424001202123 |
11 | 38614565593a62 |
12 | 12765066143637 |
13 | 57a0c13520a75 |
14 | 242c7abbd0dbd |
15 | 101296311e4ed |
hex | 769eb44307cb |
130424001202123 has 2 divisors, whose sum is σ = 130424001202124. Its totient is φ = 130424001202122.
The previous prime is 130424001202073. The next prime is 130424001202127. The reversal of 130424001202123 is 321202100424031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130424001202123 - 237 = 130286562248651 is a prime.
It is not a weakly prime, because it can be changed into another prime (130424001202127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65212000601061 + 65212000601062.
It is an arithmetic number, because the mean of its divisors is an integer number (65212000601062).
Almost surely, 2130424001202123 is an apocalyptic number.
130424001202123 is a deficient number, since it is larger than the sum of its proper divisors (1).
130424001202123 is an equidigital number, since it uses as much as digits as its factorization.
130424001202123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 130424001202123 its reverse (321202100424031), we get a palindrome (451626101626154).
The spelling of 130424001202123 in words is "one hundred thirty trillion, four hundred twenty-four billion, one million, two hundred two thousand, one hundred twenty-three".
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